\documentstyle{SibMatJ} % \TestXML \topmatter \Author Song \Initial Y. \Gender he \Sign Yanbo Song \Email syb888202106\@163.com \AffilRef 1 \endAuthor \Affil 1 \Division School of Information Engineering \Organization Xi'an University \City Xi'an \Country China \endAffil \datesubmitted September 25, 2025\enddatesubmitted \daterevised February 16, 2026\enddaterevised \dateaccepted February 17, 2026\enddateaccepted \UDclass 511.32 %èç ïðåæíåé ñòàòüè \?11N05, 11N35, 11L07 \endUDclass \title On Numbers of the Form $\theta\lfloor n^c\rfloor+\varphi$ with Smooth Indices \endtitle \abstract In this paper, we study two problems about numbers of the form $\theta\lfloor n^c\rfloor+\varphi$ with smooth indices. First, let $1 5$ be a real number. Then there are infinitely many $y$-smooth numbers $n$ such that $$ \|\theta \lfloor n^c\rfloor + \varphi\| < n^{-\frac{(3-2c)(1-1/T)}{27-1/T}+100\varepsilon}, $$ where $y=(\log n)^{T}$. Second, let $11$, by (1.14) in the paper [3] we have $$ x^{1-1/\kappa-\varepsilon}\leq\Psi(x, (\log x)^\kappa)\leq x^{1-1/\kappa+\varepsilon} \quad (\text{as } x\to\infty). \tag1 $$ Because of this sparsity, many results about smooth numbers from this %\? 2 this example above were until recently only known conditional on assumptions such as the GRH. %\?1 ðàç On the other hand, the following Diophantine inequality $$ \| \theta n + \varphi \| 5$ be a real number. %\?è ýòî real number There are infinitely many $n\in \Bbb{N}$ free of prime factors greater than $(\log n)^T$ such that $$ \|\theta \lfloor n^c\rfloor + \varphi\| < n^{-\frac{(3-2c)(1-1/T)}{27-1/T}+100\varepsilon}. \tag4 $$ \endproclaim The Piatetski-Shapiro prime is a fundamental object in analytic number theory, named after the Soviet mathematician Israel Moiseevich Piatetski-Shapiro. It refers to primes of the form $\lfloor n^c\rfloor$, where $c>1$ is a real. In 1953 Piatetski-Shapiro [14] showed that there are infinitely many Piatetski-Shapiro primes for $c\in(1,12/11)$. It is worth emphasizing that the range $c\in(1,12/11)$ was improved by Kolesnik [15], Heath-Brown [16], Kolesnik [17] and Liu and Rivat [18]. The best known result is due to Rivat and Sargos [19], which improved the range for $c$ to $(2426/2817,1)$. Inspired by the above research, we study the almost prime of the form $\lfloor\theta\lfloor n^c\rfloor+\varphi\rfloor$ with smooth indices. Whether there exist primes of the form $\lfloor\theta\lfloor n^c\rfloor+\varphi\rfloor$ with smooth indices is still an open problem. Before stating \Par*{Theorem 2}, we give the definitions of the type of an irrational number and the $R$-almost primes. \specialhead Type of an irrational number \endspecialhead For an irrational number $\theta$, its type $\tau$ is defined as follows: $$ \tau=\sup\bigl\{\rho\in\Bbb{R}: \liminf\Sb n\rightarrow\infty \\ n\in\Bbb{Z}^+\endSb n^{\rho}\|n\alpha\|=0\bigr\}, \tag5 $$ where $\|u\|$ denotes the distance of $u$ from the nearest integer. By Dirichlet's approximation theorem, we have $\tau\geq1$. If $\theta$ is of finite type $\tau$, then $\theta^{-1}$ and $k\theta$ are also of finite type $\tau$. \specialhead $R$-Almost primes \endspecialhead For every integer $R\geq1$, we say that a natural number is an $R$-almost prime if it has at most $R$ prime factors, counted with multiplicity. \proclaim{Theorem 2} Let $1 y$. We define $P^{+}(n)$ to be the largest prime factor of $n$. We will frequently use $\varepsilon$ with an abuse of notation %\? to mean a small positive number, possibly a different one each time. Given a real number $x$, we write $e(x)=e^{2\pi ix}$. We use $\lfloor t\rfloor,\{t\}$ and $\|t\|$ to denote the integral part of $t$, the fractional part of $t$ and the distance from $t$ to the nearest integer, respectively. The notation $n\sim N$ means $N0$, $c>0$, and $\phi$ be reals. Then $d|\lfloor\theta\lfloor n^{c}\rfloor+\phi\rfloor$ if and only if $E_{\theta,c,\phi,d}(n):=\lfloor\frac{\theta\lfloor n^{c}\rfloor+\phi}{d}\rfloor -\lfloor\frac{\theta\lfloor n^{c}\rfloor+\phi-1}{d}\rfloor=1$. \endproclaim \demo{Proof} The proof of this lemma is easy, we left it to readers. \qed\enddemo \proclaim{Lemma 8} Suppose that $2\leq y\leq R\leq n\leq x$, with $n\in S(x,y)$. Then there is a unique triple $(p, u, v)$ satisfying \Item (i) $n=puv$, \Item (ii) $p\leq y$, \Item (iii) $R/p0$ on $I$ then $$ \sum_{n\in I}e(f(n))\ll \lambda^{-1}. $$ \endproclaim \demo{Proof} This is Theorem 2.1 in [22]. \qed\enddemo \proclaim{Lemma 10} If $Z$ is large enough positive real %\? then $$ \int\limits_{-1/2}^{1/2}\biggl|\sum_{r\in I}e(\alpha r)\biggr|d\alpha\ll\log Z, $$ where $I$ is an interval with $I\subset[Z,2Z]$. \endproclaim \demo{Proof} We have $$ \int\limits_{-1/2}^{1/2}\biggl|\sum_{r\in I}e(\alpha r)\biggr|d\alpha =\int\limits_{-1/Z}^{1/Z}\biggl|\sum_{r\in I}e(\alpha r)\biggr|d\alpha+\int\limits_{1/Z}^{1/2} \biggl|\sum_{r\in I}e(\alpha r)\biggr|d\alpha+\int\limits_{-1/2}^{-1/Z}\biggl|\sum_{r\in I}e(\alpha r)\biggr|d\alpha =:I_1+I_2+I_3. $$ By trivial estimation we have $$ I_1\leq\int\limits_{-1/Z}^{1/Z}Zd\alpha\ll1. \tag7 $$ By \Par*{Lemma 9} we have $$ I_2\leq\int\limits_{1/Z}^{1/2}\alpha^{-1}d\alpha\ll\log Z. \tag8 $$ Similarly $$ I_3\ll\log Z. \tag9 $$ Combining \Tag(7)--\Tag(9) we have $$ \int\limits_{-1/2}^{1/2}\biggl|\sum_{r\in I}e(\alpha r)\biggr|d\alpha\ll\log Z. $$ This completes the proof of this lemma. %\?2 this \qed\enddemo \head 4. Proof of \Par*{Theorem 1} \endhead By Dirichlet's approximation theorem, for any irrational number $\theta$, there exists an integer $q$ such that $$ \Bigl|\theta - \frac aq\Bigr| < \frac 1{q^2}, \quad (a,q)= 1. \tag10 $$ We may suppose that $\varepsilon$ is sufficiently small, so that $$ \gamma : = \frac{(3-2c)(1-1/T)}{27-1/T}-100\varepsilon $$ is positive. Define $x$ by $$ x^{\frac{c+\gamma }2} = q. \tag11 $$ Suppose that $n \in \Bbb{N}$ satisfies $$ \Bigl\|\frac{a[n^c]}q + \varphi\Bigr\| \le x^{-\gamma }, \quad n \in S(x,y), \quad y = (\log x)^T. \tag12 $$ This implies $$ \|\theta [n^c] + \varphi\| \le x^{-\gamma } + \Bigl|\theta - \frac aq\Bigr| \cdot x^c \le x^{-\gamma } + \frac{x}{x^{1+\gamma }} < n^{-\frac{(3-2c)(1-1/T)}{27-1/T}+100\varepsilon} $$ from \Tag(10)--\Tag(12). Hence it will suffice to show that \Tag(12) has a solution $n$. Let $S = S_2(x^{\frac{1+\gamma }2}, y)$ and $J = S_2(x^{\frac{1-\gamma }2},y)$. By (1.1), %\?íåò òàêîãî, ìîæåò, \Tag(11) \iftex $$ \align x^{\frac{1+\gamma }2\, (1-\frac 1T) - \frac\varepsilon{16}} &\ll |S| \ll x^{\frac{1+\gamma }2 (1 - \frac 1T)+\frac \varepsilon{16}}, \tag13 \\ x^{\frac{1-\gamma }2\, (1-\frac 1T) - \frac\varepsilon{16}} &\ll |J| \ll x^{\frac{1-\gamma }2 (1 - \frac 1T)+\frac \varepsilon{16}}. \tag14 \endalign $$ \else $$ x^{\frac{1+\gamma }2\, (1-\frac 1T) - \frac\varepsilon{16}} \ll |S| \ll x^{\frac{1+\gamma }2 (1 - \frac 1T)+\frac \varepsilon{16}}, \tag13 $$ $$ x^{\frac{1-\gamma }2\, (1-\frac 1T) - \frac\varepsilon{16}} \ll |J| \ll x^{\frac{1-\gamma }2 (1 - \frac 1T)+\frac \varepsilon{16}}. \tag14 $$ \fi We will show that there are solutions of \Tag(12) with $$ n = uv, \quad u \in S, \quad v \in J. $$ Suppose there are no such solutions of \Tag(12). Let $$ S_h = \sum_{u\in S} \ \sum_{v \in J} e\Bigl(\frac{ha[u^cv^c]}q\Bigr). $$ Let $H = \lfloor x^\gamma \rfloor + 1$. We deduce from \Par*{Lemma 1} and \Tag(13), \Tag(14) that $$ \sum_{h=1}^H |S_h| \gg g x^{1 - \frac 1T - \frac \varepsilon 8}. \tag15 $$ Now we estimate the upper bounds of $\sum_{h=1}^H |S_h|$. First we have $$ \sum_{h=1}^H |S_h| \ll x^{\gamma}\max_{h\leq H}|S_h|. \tag16 $$ By \Par*{Lemma 2} with $Z=\lfloor x^{\gamma+\varepsilon}\rfloor+1$, we have $$ \align S_h &=\sum_{u\leq x^{\frac{1+\gamma}{2}(1-1/T)}}a(u)\sum_{v\leq x^{\frac{1-\gamma}{2}(1-1/T)}}b(v)e(ha[u^cv^c]/q)\sum_{z=0}^{2Z-1}g_z(u^cv^c)\\ &=\sum_{z=0}^{2Z-1}\sum_{u\leq x^{\frac{1+\gamma}{2}(1-1/T)}}a(u)\sum_{v\leq x^{\frac{1-\gamma}{2}(1-1/T)}}b(v)e(ha[u^cv^c]/q)g_z(u^cv^c)\\ &=\sum_{z=0}^{2Z-1}\sum_{u\leq x^{\frac{1+\gamma}{2}(1-1/T)}}a(u)\sum_{v\leq x^{\frac{1-\gamma}{2}(1-1/T)}}b(v)(e(ha(u^cv^c-z/2Z)/q)\\ &\qquad+O(H/Z))g_z(u^cv^c)\\ &=\sum_{z=0}^{2Z-1}\sum_{u\leq x^{\frac{1+\gamma}{2}(1-1/T)}}a(u)\sum_{v\leq x^{\frac{1-\gamma}{2}(1-1/T)}}b(v)e(ha(u^cv^c-z/2Z)/q)\\ &\qquad\times g_z(u^cv^c)+O(x^{1-1/T-\varepsilon}), \endalign $$ where $a(u)$ and $b(v)$ are the indicator function %\?functions of smooth number. By \Par*{Lemma 2}, we have $$ g_z(u^cv^c)=\sum_{|l|\leq Z\log^4 x}\beta_z^{(l)}e(lu^cv^c)+O(x^{-\log\log x}). $$ This implies $$ \align S_h &=\sum_{z=0}^{2Z-1}\sum_{|l|\leq Z\log^4 x}\beta_z^l\sum_{u\leq x^{\frac{1+\gamma}{2}(1-1/T)}}a(u)\sum_{v\leq x^{\frac{1-\gamma}{2}(1-1/T)}}b(v)e((ha/q+l)u^cv^c)\\ &\qquad +O(x^{1-1/T-\varepsilon})\\ &\ll x^{\gamma+\varepsilon}|\sum_{u\leq x^{\frac{1+\gamma}{2}(1-1/T)}}a(u)\sum_{v\leq x^{\frac{1-\gamma}{2}(1-1/T)}}b(v)e((ha/q+l)u^cv^c)|\\ &\qquad+O(x^{1-1/T-\varepsilon})\\ &=:x^{\gamma+\varepsilon}S^{'}+O(x^{1-1/T-\varepsilon}). \endalign $$ By \Par*{Lemma 3} with $Q=\lfloor x^{4\gamma+8\varepsilon}\rfloor+1$ (note that $Q\ll x^{\frac{1+\gamma}{2}(1-1/T)}-\varepsilon$), we have $$ S^{'2}\ll \frac{x^{2(1-1/T)}}{Q}+\frac{{x^{1-1/T}}}{Q}\sum_{1\leq s\leq Q}\,\sum_{u\sim x{\frac{(1+\gamma)(1-1/T)}{2}}} %\times %\? \,\biggl|\sum_{v\sim x^{\frac{(1-\gamma)(1-1/T)}{2}}}e((ha/q+l)su^{c-1}v^c)\biggr|. $$ Note that $|ha/q+l|\geq1/q$, and apply \Par*{Lemma 4} to the innermost sum, we see the innermost sum is $$ \ll x^{\frac{1+\gamma}{2}(1-\frac{1}{T})}x^{\frac{\gamma+\varepsilon}{2}}Q^{1/2}u^{\frac{c-1}{2}}v^{\frac{c-2}{2}}+q^{1/2}u^{\frac{1-c}{2}}v^{\frac{2-c}{2}}. $$ It thus follows that $$ S^{'}\ll x^{1-1/t-3\gamma-\varepsilon}. $$ Upon collecting the estimates above, we find that $$ \sum_{n=1}^HS_h\ll x^{1-1/t-\varepsilon}. $$ This leads to a contradiction. This completes the proof of the theorem. \head 5. Proof of \Par*{Theorem 2} \endhead Let $A=\{\lfloor\theta\lfloor n^c\rfloor+\phi\rfloor|\text{$n$ is a $y$-smooth number and $n\leq x$}\}$. First let $D$ be the level of the distribution of $A$. By \Par*{Lemma 5} with $H=D\log^3x$ and \Par*{Lemma 7} we have $$ \align \sum_{d\leq D}\max_{\gcd(s,d)=1}\Bigl|\bigl| &\{a\in A,\,a\equiv s\bmod d\}\bigr|-{\frac{\Psi(x,y)}{d}}\Bigr| \\ &=\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb\Bigl(\Bigl\lfloor\frac{\theta\lfloor n^{c}\rfloor+\phi}{d}\Bigr\rfloor -\Bigl\lfloor\frac{\theta\lfloor n^{c}\rfloor+\phi-1}{d}\Bigr\rfloor\Bigr)-\frac{\Psi(x,y)}{d}\biggr| \\ &=\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb\frac{1}{d} +O\biggl(\sum\Sb n\leq x\\P^+(n)\leq y\endSb\psi\Bigl(\frac{\theta \lfloor n^c\rfloor+\phi}{d}\Bigr)\biggr) \\ &\qquad+ O\biggl(\sum\Sb n\leq x\\P^+(n)\leq y\endSb\psi\Bigl(\frac{\theta \lfloor n^c\rfloor+\phi-1}{d}\Bigr)\biggr)-\frac{\Psi(x,y)}{d}\biggr|\\ &\ll\sum_{d\leq D}\biggl(\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb\psi\Bigl(\frac{\theta \lfloor n^c\rfloor+\phi}{d}\Bigr)\biggr|+\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb\psi\Bigl(\frac{\theta \lfloor n^c\rfloor+\phi-1}{d}\Bigr)\biggr|\biggr)\\ &\ll\sum_{d\leq D}\sum_{1\leq h\leq H}\frac{1}{h}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta h\lfloor n^c\rfloor}{d}\Bigr)\biggr|+O\Bigl(\frac{\Psi(x,y)}{\log^3x}\Bigr)\\ &\ll\max_{1\leq h\leq H}\log x\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta h\lfloor n^c\rfloor}{d}\Bigr)\biggr|+O\Bigl(\frac{\Psi(x,y)}{\log^3x}\Bigr). \endalign $$ By \Par*{Lemma 2} with $Z=D\log^5x$ we have $$ \align &\sum_{d\leq D}\max_{\gcd(s,d)=1}\Bigl|\bigl|\{a\in A,\,a\equiv s\bmod d\}\bigr|-\frac{\Psi(x,y)}{d}\Bigr|\\ &\ll\max_{1\leq h\leq H}\log x\sum_{z=0}^{2Z-1}\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta h\lfloor n^c\rfloor}{d}\Bigr)\biggr|g_z(n^c)+O\Bigl(\frac{\Psi(x,y)}{\log^3x}\Bigr) \\ &\ll\max_{1\leq h\leq H}\log x\sum_{z=0}^{2Z-1}\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta hn^c}{d}-\frac{\theta z}{2dZ}\Bigr)+O\Bigl(\frac{h\theta}{dZ}\Bigr)\biggr|g_z(n^c)+O\Bigl(\frac{\Psi(x,y)}{\log^3x}\Bigr)\\ &\ll\max_{1\leq h\leq H}\log x\sum_{z=0}^{2Z-1}\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta hn^c}{d}\Bigr)\biggr|g_z(n^c)\\ &\qquad+O\Biggl(\log x\sum_{z=0}^{2Z-1}g_z(n^c)\sum_{d\leq D}\sum\Sb n\leq x\\P^+(n)\leq y\endSb\frac{h\theta}{dZ}\Biggr) +O\Bigl(\frac{\Psi(x,y)}{\log^3x}\Bigr)\\ &\ll\max_{1\leq h\leq H}\log x\sum_{z=0}^{2Z-1}\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta hn^c}{d}\Bigr)\biggr|g_z(n^c)+\frac{\Psi(x,y)}{\log^3x}\\ &\ll\max_{1\leq h\leq H}\log x\sum_{z=0}^{2Z-1}\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta hn^c}{d}\Bigr)g_z(n^c)\biggr|+\frac{\Psi(x,y)}{\log^3x}\\ &\ll\max_{1\leq h\leq H}\log x\sum_{z=0}^{2Z-1}\sum_{d\leq D}\,\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\frac{\theta hn^c}{d}\Bigr)\sum_{|r|\leq Z\log^4x}\beta_r^{(z)}e(rn^c)\biggr|+\frac{\Psi(x,y)}{\log^3x}\\ &\ll\max_{1\leq h\leq H}\log x\sum_{z=0}^{2Z-1}\sum_{d\leq D}\sum_{|r|\leq Z\log^4x}\beta_r^{(z)}\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\Bigl(\frac{\theta h}{d}+r\Bigr)n^c\Bigr)\biggr|+\frac{\Psi(x,y)}{\log^3x}\\ &\ll\max_{1\leq h\leq H}ZD\log^5x\max_{d\leq D}\biggl|\sum\Sb n\leq x\\P^+(n)\leq y\endSb e\Bigl(\Bigl(\frac{\theta h}{d}+r\Bigr)n^c\Bigr)\biggr|+\frac{\Psi(x,y)}{\log^3x}. \endalign $$ Now we estimate the innermost sum in the last expression. Let $s=\frac{\theta h}{d}+r$, recall that the type of $\theta$ is~$\tau$, the type of the irrational $\theta/d$ is also $\tau$, then by the definition of the type of the irrational number, we have $\|h\theta/d\|>Ch^{-\tau-\varepsilon}$, where $C$ is a constant. By \Par*{Lemma 8} we have $$ \sum\Sb n \sim M \\ P^{+}(m) \leq y\endSb e(sn^c) =\sum\Sb p \leq y\endSb \sum\Sb M_1 / p\max\Bigl\{\frac{8+\tau}{c-\varepsilon},\frac{9}{2-c-\varepsilon}\Bigr\}+\delta_R=\max\Bigl\{\frac{8+\tau}{c-\varepsilon},\frac{9}{2-c-\varepsilon}\Bigr\}+0.124820. $$ we have $$ \bigl|\{n\in S(x,y)|\lfloor\theta\lfloor n^c\rfloor+\varphi\rfloor \text{ is an $R$-almost prime}\}\bigr|\gg \frac{x}{\log^2x}, $$ where $x^{\varepsilon}